2x^2+3y^2=20

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Solution for 2x^2+3y^2=20 equation:


Simplifying
2x2 + 3y2 = 20

Solving
2x2 + 3y2 = 20

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3y2' to each side of the equation.
2x2 + 3y2 + -3y2 = 20 + -3y2

Combine like terms: 3y2 + -3y2 = 0
2x2 + 0 = 20 + -3y2
2x2 = 20 + -3y2

Divide each side by '2'.
x2 = 10 + -1.5y2

Simplifying
x2 = 10 + -1.5y2

Reorder the terms:
-10 + x2 + 1.5y2 = 10 + -1.5y2 + -10 + 1.5y2

Reorder the terms:
-10 + x2 + 1.5y2 = 10 + -10 + -1.5y2 + 1.5y2

Combine like terms: 10 + -10 = 0
-10 + x2 + 1.5y2 = 0 + -1.5y2 + 1.5y2
-10 + x2 + 1.5y2 = -1.5y2 + 1.5y2

Combine like terms: -1.5y2 + 1.5y2 = 0.0
-10 + x2 + 1.5y2 = 0.0

The solution to this equation could not be determined.

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